![]() ![]() ![]() With all three plugged in, the contribution of each output will be a maximum of 333mV. This solves the loading issue (now each output sees 3.3k which isn't as bad), but not the voltage dividing issue. the leftmost output will see R1 || (R2 + R3)) One is that in order to keep a low impedance output you need to use low value resistors and this loads each output excessively, plus creates a voltage divider between the outputs.Įach output in the above example would see a 150 ohm load (e.g. A simple passive resistive mixer is basic, but a bad solution for a couple of reasons:
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